Asked by lilman
The length of a rectangle is 9.7cm more than 4 times the width. If the perimeter of the rectangle is 9.1cm what are its dimensions?
Could someone please explain, not looking for just answer, needing to know how to do it.
Could someone please explain, not looking for just answer, needing to know how to do it.
Answers
Answered by
Steve
width = w
length = 4w+9.7
p = 2(w + 4w+9.7) = 9.1
w = -1.03
That seems odd, since widths are usually positive. But, looking at the data given, it's impossible for the length to be greater than 9.7 and have the perimeter be only 9.1
Better fix it if you want a sensible answer.
length = 4w+9.7
p = 2(w + 4w+9.7) = 9.1
w = -1.03
That seems odd, since widths are usually positive. But, looking at the data given, it's impossible for the length to be greater than 9.7 and have the perimeter be only 9.1
Better fix it if you want a sensible answer.
Answered by
lilman
Steve you were right missed wrote.the length is 9.7cm more than 4 times the width and the perimeter is 91.4cm.
Answered by
sarah
if anyone’s taking algebra 2 on connexus pls add me on insta @lvr.sarah im tryna find someone to work w in that class lmfao
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