Asked by Shannon
1.A hiker started to walk from her campsite heading east with a velocity of 5 m\s after 6 seconds, she attained a velocity of 7 m\s. What is the average velocity of the hiker? What is the hiker’s acceleration? If the hiker continues walking for another 60 seconds, how far east can she go?
Answers
Answered by
bobpursley
a. avgvelocity=(final+starting)/2= 6m/s
acceleration=changevelocity/time=1/3 m/s^2
distance=distance first six seconds+distance for last 54 seconds
= avgvelocity*6+7*54=36m+378m
acceleration=changevelocity/time=1/3 m/s^2
distance=distance first six seconds+distance for last 54 seconds
= avgvelocity*6+7*54=36m+378m
Answered by
xZ
456
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