how many liters of water will have to be added to 1125 liters of 45% solution of acid so that the resulting mixture will contain more than 25% but less than 30% acid content.

Answer 1

(1125+x)*25 < 1125*45 < (1125+x)*30
562.5 < x < 900

Answer 2

Let x litres of water will add to 1125 litres of 45% sol. So it give results mixture will contain more than 25% but less than 30% acid content.
(1125 + x)25< 1125*45 <(1125 + x)30 28125+25x<50625< 33750+30x 25x<22500 or 30x>16875 x<900 or x>562.5

Answer 3

Answer:
Let x litres of water will add to 1125 litres of 45% sol. So it give results mixture will contain more than 25% but less than 30% acid content.
(1125 + x)25< 1125*45 <(1125 + x)30 28125+25x<50625< 33750+30x 25x<22500 or 30x>16875 x<900 or x>562.5

Answer 4

Let x litres of water is required to be added.
Then, total mixture = ( x + 1125) litres
It is evident that the amount of acid contained in the resulting mixture is 45% of 1125 litres.
This resulting mixture will contain more than 25% but less than 30% acid content.
∴30% of (1125 + x ) > 45% of 1125
And, 25% of (1125 + x ) < 45% of 1125
30 % of (1125 + x ) > 45% of 1125

25% of (1125 + x ) < 45% of 1125

∴562.5 < x < 900
Thus, the required number of litres of water that is to be added will have to be more than 562.5 but less than 900.