Asked by Aa

From t = 0 to t = 3.30 min, a man stands still, and from t = 3.30 min to t = 6.60 min, he walks briskly in a straight line at a constant speed of 1.76 m/s. What are (a) his average velocity vavg and (b) his average acceleration aavg in the time interval 1.00 min to 4.30 min? What are (c) vavg and (d) aavg in the time interval 2.00 min to 5.30 min?
Answered by bobpursley
do you have a question about this?

avgvelociyt=total distance/total time

avg acceleratio=changevelociyt/total time
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