Question

a boy is b years old and his father is 6 times as old as him. find the father's age. and also the sum of their ages in years time?

Answer 1

son's present age ---- x
father's present age -- 6x

"the sum of their ages in years time?"
----- check this for typo

e.g if number of years is 12 , just add 12 to each of the ages for the sum (x+12) + (6x+12) = 7x + 24

Answer 2

6byears;(7b+2y)years

Answer 3

Son's age= b
Since the father's age is 6 'times' (multiplication) the son's age, his age will be= 6b
After y years of time, the sum of their ages will be= 6b+y+b+y
= (7b+2y) years