Asked by Chad
How many moles of H_2 are needed to produce 13.27g of NH_3?
Answers
Answered by
Steve
well one mole of NH3 has 3 moles of H
1 mole of H2 has 2 moles of H
each mole of NH3 requires 3/2 moles of H2
mol wt of NH3 = 14 + 3*1 = 17
so you need 3/2 * (13.27 / 17) = 1.17
1 mole of H2 has 2 moles of H
each mole of NH3 requires 3/2 moles of H2
mol wt of NH3 = 14 + 3*1 = 17
so you need 3/2 * (13.27 / 17) = 1.17
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