Asked by maxine
a student paid little attention to the size of his burner flame while heating a 0.979 gram sample of calcium oxalate monohydrate. The final mass of the cooled solid was 0.670 gram. Was the reaction product anhydrous calcium oxalate?
Answers
Answered by
DrBob222
You want to convert 0.979 g CaC2O4.H2O to mass CaC2O4 an compar with 0.670g.
Convert 0.979 g CaC2O4.H2O to mols CaC2O4.H2O, then to mols CaC2O4, then to grams CaC2O4.
0.979g CaC2O4.H2O x (1 mol CaC2O4.H2O/molar mass CaC2O4.H2O) x (1 mol CaC2O4/1 mol C2O4.H2O) x (molar mass CaC2O4/1 mol CaC2O4) = ? g CaC2O4. Compare with 0.670 g.
Convert 0.979 g CaC2O4.H2O to mols CaC2O4.H2O, then to mols CaC2O4, then to grams CaC2O4.
0.979g CaC2O4.H2O x (1 mol CaC2O4.H2O/molar mass CaC2O4.H2O) x (1 mol CaC2O4/1 mol C2O4.H2O) x (molar mass CaC2O4/1 mol CaC2O4) = ? g CaC2O4. Compare with 0.670 g.
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