Question

Integral of 1/root(2x-x^2)dx

Answer 1

2x-x^2 = 1 - (1-x)^2
let u = 1-x
du = -dx
now you have

∫-du/√(1-u^2) = -arcsin(u) = -arcsin(1-x)+C

Answer 2

*This is not an answer*

Thanks Steve that really helps!!!

*This is not an answer*