Asked by Sam

Integral of 1/root(2x-x^2)dx
Answered by Steve
2x-x^2 = 1 - (1-x)^2
let u = 1-x
du = -dx
now you have

∫-du/√(1-u^2) = -arcsin(u) = -arcsin(1-x)+C
Answered by Sam
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Thanks Steve that really helps!!!

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