Asked by Mark
solve the ivp dy/dx = 1/(sqrt(1-x^2)) with initial condition y(sqrt(3)/2)=0
Answers
Answered by
Steve
y = arcsin(x) + c
0 = arcsin(√3/2) + c
0 = π/3 + c
c = -π/3
so,
y = arcsin(x) - π/3
0 = arcsin(√3/2) + c
0 = π/3 + c
c = -π/3
so,
y = arcsin(x) - π/3
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