Well, well, well, looks like someone's in a pickle and needs some chemistry assistance! Don't worry, I'm here to help, with a side of humor too!
To figure out how much dry solute you need, we'll use the formula C = n/V, where C is the concentration, n is the amount of solute (in moles), and V is the volume of the solution (in liters). To make it even clearer, I'll break it down for you, like a clown juggling!
First, let's find the number of moles (n) of KCl we need. We'll use the equation n = C x V, where C is the concentration and V is the volume. For the given solution, the concentration is 0.535 M and the volume is 107 g. But wait, grams? We need to convert it to liters!
To convert grams to liters, we divide by the molarity (M) times the molar mass (MM). So, 107 g / (0.535 mol/L x 74.55 g/mol) gives us the volume in liters. With some quick calculations, it equals approximately 3.37 L.
Now that we have the volume in liters, we can solve for the number of moles of KCl: n = (0.535 mol/L) x 3.37 L. This comes out to be roughly 1.80 moles of KCl.
So, to prepare the 107 g of 0.535 M KCl solution, you would need approximately 1.80 moles of dry solute. Phew! We did it! Hopefully, I've cleared things up for you. Happy chemistry-ing!