Asked by Jon
( / means absolute value)
Solve: 3+/2y-1/>=1. Graph the solution set on a number line.
The number line I have is:
-5 -4 -3 -2 -1 0 1 2 3 4 5 6
I'm confused on what to do.
Solve: 3+/2y-1/>=1. Graph the solution set on a number line.
The number line I have is:
-5 -4 -3 -2 -1 0 1 2 3 4 5 6
I'm confused on what to do.
Answers
Answered by
Reiny
3+ │2y-1│ ≥ 1 or
│2y-1│ ≥ -2
this has an intuitive solution.
by the definition of absolute value, the left side can only be positive or zero.
any positive value or zero ≥ -2
so the solution would be the entire number set. So draw a solid line on your number line with arrows in either direction.
│2y-1│ ≥ -2
this has an intuitive solution.
by the definition of absolute value, the left side can only be positive or zero.
any positive value or zero ≥ -2
so the solution would be the entire number set. So draw a solid line on your number line with arrows in either direction.
Answered by
Jon
I have to show my work so is that ALL I have to do? 3+ ©¦2y-1©¦ ¡Ý 1 or
©¦2y-1©¦ ¡Ý -2
©¦2y-1©¦ ¡Ý -2
Answered by
Reiny
by saying,
"by definition │anything│ ≥ -2" you have shown your work.
"by definition │anything│ ≥ -2" you have shown your work.
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