Asked by Lexxie

A watermelon cannon fires a watermelon vertically up into the air at a velocity of + 9.50 m/s, starting from an initial position 1.20 meters above the ground. When the watermelon reaches the peak of its flight, what is the elapsed time in sec?

Answers

Answered by Henry
t = (V-Vo)/g = )-9.50)/-9.8 = 0.969 s.
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