a = -ug = -0.54*9.8 = -5.29 m/s^2.
V = Vo + at = 18.3 - 5.29*1.33=11.26 m/s
V = Vo + at = 18.3 - 5.29*1.33=11.26 m/s
Let's start by finding the deceleration of the automobile. The deceleration can be calculated using the formula:
a = μ * g
where:
a is the deceleration
μ is the coefficient of kinetic friction
g is the acceleration due to gravity (approximately 9.8 m/s²)
Given that the coefficient of kinetic friction is 0.540, we can substitute the values into the formula:
a = 0.540 * 9.8 = 5.292 m/s²
Now, using the equation of motion:
v = u + at
where:
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
Given that the initial velocity u is 18.3 m/s and the time t is 1.33 seconds, and the acceleration a is -5.292 m/s² (negative because it's deceleration), we can substitute the values:
v = 18.3 + (-5.292) * 1.33
Computing the equation:
v = 18.3 - 7.056
v = 11.244 m/s
Therefore, the speed of the automobile after 1.33 seconds have elapsed is 11.244 m/s.