A policeman travelling 60 km/h spots a speeder ahead , so he accelerates his vehicle at a steady rate of 2.22 m/s^2 for 4.00 s, at which time he catches up with the speeder.

Question

a) How fast was the policeman travelling in m/s?
b) How fast is the police car travelling after 4.00 s? Give answer in both m/s and km/h?
c) If the speeder has a constant velocity, sketch the motion of both the speeder and police car on a speed vs. time graph?

Answer 1

See your 9:32am post.

Answer 2

a.) 25.6m/s

Answer 3

60km/h*1km/1000m=6000m/h
6000m/h*1h/3600=16.6m/s

v=Vo+at
v=16.6+(2.22)(4.00)=25.48 m/s

Answer 4

a)60km/h*1km/1000m=6000m/h
6000m/h*1h/3600=16.6m/s

v=Vo+at
v=16.6+(2.22)(4.00)=25.48 m/s

b)