Asked by kevin
I have a few questions that I don't understand hope someone can help.
1)write an equation of th line, in point slope form, that passes through the two given points. (-17,8),(3,-2)
I figured (y-8)=-2(x+17) not sure
2) the graph of g(x) is f(x) vertically compressed by a factor of 1/7 and reflected in the x-axis what is the function rule for g(x)given f(x)=2x.
not sure about this one
3)determine whether y varies directly with x if so find the constant of variation k and write the equation.
x y
7 11
8 13
9 15
10 17
I know you start with y=kx but then I'm lost.
not looking for just answers but if someone can explain I'd appreciate it
1)write an equation of th line, in point slope form, that passes through the two given points. (-17,8),(3,-2)
I figured (y-8)=-2(x+17) not sure
2) the graph of g(x) is f(x) vertically compressed by a factor of 1/7 and reflected in the x-axis what is the function rule for g(x)given f(x)=2x.
not sure about this one
3)determine whether y varies directly with x if so find the constant of variation k and write the equation.
x y
7 11
8 13
9 15
10 17
I know you start with y=kx but then I'm lost.
not looking for just answers but if someone can explain I'd appreciate it
Answers
Answered by
kevin
on number 3 y=kx
so would i divide y by x and if so I get 1.57, 1.62, 1.66, and 1.7..Is this right?
so would i divide y by x and if so I get 1.57, 1.62, 1.66, and 1.7..Is this right?
Answered by
Steve
#1. If not sure, plug in the points and see whether they satisfy your equation. you will see that they don't even come close
The (y-8) and (x+17) bits are ok, but how did you come up with a slope of -2? (-2-8)/(3+17) = -1/2
Looks like you used ∆x/∆y for the slope, rather than ∆y/∆x!
#2: you want g(x) which produces a height 1/7 of f(x). So,
g(x) = 1/7 f(x)
Now, you want to reflect g(x) around the x-axis, so
h(x) = -g(x)
h(x) = -1/7 f(x) = -1/7 (2x) = -2/7 x
check: f(1) = 2
h(1) = -2/7 shrunk, reflected
that is correct. Since the ratio changes, it is not a constant k.
y does not vary directly with x
In fact, y increases by 2 for every increase in x by 1. So,
y = 2x-3
That pesky -3 fouls up the direct variation.
The (y-8) and (x+17) bits are ok, but how did you come up with a slope of -2? (-2-8)/(3+17) = -1/2
Looks like you used ∆x/∆y for the slope, rather than ∆y/∆x!
#2: you want g(x) which produces a height 1/7 of f(x). So,
g(x) = 1/7 f(x)
Now, you want to reflect g(x) around the x-axis, so
h(x) = -g(x)
h(x) = -1/7 f(x) = -1/7 (2x) = -2/7 x
check: f(1) = 2
h(1) = -2/7 shrunk, reflected
that is correct. Since the ratio changes, it is not a constant k.
y does not vary directly with x
In fact, y increases by 2 for every increase in x by 1. So,
y = 2x-3
That pesky -3 fouls up the direct variation.
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