Asked by Johnathan
Prove that:
P(A n B^c) = P(A U B) - P(B)
and
P(A n B^c) = P(A) - P(A n B)
P(A n B^c) = P(A U B) - P(B)
and
P(A n B^c) = P(A) - P(A n B)
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