Question
A skier leaves the end of a horizontal ski jump at 22.0 m/s and falls 3.20 m before landing. Neglecting friction, how far horizontally does the skier travel in the air before landing?
Answers
bobpursley
time to fall 3.2 m
h=1/2 g t^2
t= sqrt (2*3.2/9.8)
distance horizontal=22*timetofall
h=1/2 g t^2
t= sqrt (2*3.2/9.8)
distance horizontal=22*timetofall
jt
17.7
donald
22m
donald
21.6