Asked by Becca
Wes and Lindsay stand on the roof of a building. Wes leans over the edge and drops an apple. Lindsay waits, 1.25s afrer Wes releases his fruit and throws an orange straight down at 28 m/s. Both pieces of fruit hit the ground simultaneously. Calculate the common height from which the fruit were released. Ignore the effects of air resistence.
Answers
Answered by
bobpursley
the height is the same, as is the time (one is 1.25 seconds longer)
happle=1/2 g t^2
horante=-28*(t-1.25)+1/2 g (t-1.25)^2
solve for t in the first equation
t=sqrt(2h/g)
put that t into the second equation
h=-28(sqrt(2h/g) - 1.25)-4.9(sqrt (2h/g)-1.25)^2
expand this out, the height h divides out, solve for t. Then, calculate h.
happle=1/2 g t^2
horante=-28*(t-1.25)+1/2 g (t-1.25)^2
solve for t in the first equation
t=sqrt(2h/g)
put that t into the second equation
h=-28(sqrt(2h/g) - 1.25)-4.9(sqrt (2h/g)-1.25)^2
expand this out, the height h divides out, solve for t. Then, calculate h.
Answered by
Becca
Bob, Im not getting the same answer when i do plug in the H into finding the height of the apples and oranges