Asked by shaun
three consecutive primes are summed. when the sum is squared, the result is 72,361. what is the largest of the three primes?
Answers
Answered by
Reiny
(sum of 3 consecutive primes )^2 = 72361
sum of 3 consecutive primes = 269
269/3 = 89
so the middle prime must be around 89
BUT 89 is a prime
http://primes.utm.edu/lists/small/10000.txt
the one before is 83 and the one after is 97
So the largest of these primes is 97
check:
(83+89+97)^
= 269^2
= 72361 , YEAH!
sum of 3 consecutive primes = 269
269/3 = 89
so the middle prime must be around 89
BUT 89 is a prime
http://primes.utm.edu/lists/small/10000.txt
the one before is 83 and the one after is 97
So the largest of these primes is 97
check:
(83+89+97)^
= 269^2
= 72361 , YEAH!
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