Asked by Kabe
A lighthouse that rises h = 50 ft above the surface of the water sits on a rocky cliff that extends 19 ft from its base, as shown in the figure. A sailor on the deck of a ship sights the top of the lighthouse at an angle of θ = 28.0° above the horizontal. If the sailor's eye level is 14 ft above the water, how far is the ship from the rocks?
Answers
Answered by
bobpursley
horizonal distance total=rock distance+19ft
height up to top= 50-14
Tan28=heightuptoTop/horizontal distance
tan28deg=(36/(d+14))
solve for d
height up to top= 50-14
Tan28=heightuptoTop/horizontal distance
tan28deg=(36/(d+14))
solve for d
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