A car accelerates at 2.25m/s^2 along a straight road. It passes two marks that are 30.5m apart at times t=3.80s and t=4.90s. What was the car's velocity at t=0?

Answer 1

Average speed between the marks = 30.5/1.10 = 27.73 m/s

Speed increase between marks = 2.25*1.1 = 2.475 m/s

Speed passing first mark 27.73 - 1.24 = 26.49 m/s

26.49 = Vo + 2.25*3.80

Solve for Vo