Asked by Jess
What is the pH of a 5.00E-2 M solution of acetylsalicylic acid, pKa = 3.52.
Answers
Answered by
DrBob222
...........ASA ==> H^+ + A^-
I..........0.05.....0.....0
C..........-x.......x......x
E.........0.05-x....x......x
K = 3.02E-4 = (H^+)(A^-)/(ASA)
Substitute from the ICE table into Ka and solve for (H^+), then convert to pH.
I..........0.05.....0.....0
C..........-x.......x......x
E.........0.05-x....x......x
K = 3.02E-4 = (H^+)(A^-)/(ASA)
Substitute from the ICE table into Ka and solve for (H^+), then convert to pH.
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