Asked by Anonymous
A boat with a horizontal tow rope pulls a water skier. She skies off to the side,
so the rope makes an angle of 15.0° with her direction of motion, but in the
same direction as the boat is traveling. The tension in the rope is 160 N. How
much work is done on the skier by the rope during a displacement of 400 m?
so the rope makes an angle of 15.0° with her direction of motion, but in the
same direction as the boat is traveling. The tension in the rope is 160 N. How
much work is done on the skier by the rope during a displacement of 400 m?
Answers
Answered by
Ee
Fx = 160 * cos(15) = 155N
W.D. = 155 * 400 = 62kN
W.D. = 155 * 400 = 62kN
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