Asked by Anonymous
For each of the following explain how you would prepare 1.0 L of a solution that is 0.10 M in K+. Repeat for concentrations of 1.0 × 102 ppm K+ and 1.0% w/v K+.
Answers
Answered by
DrBob222
For 0.1M K^+, you want 0.1 mol K^+/L soln.
1 mol KCl = about 74.5 g. 0.1 mol = 7.45 g KCl and that gives you 0.1 mol K^+. Therefore place 7.45 g KCl in some water, swirl until dissolved, add water to the 1 L mark, mix thoroughly.
1 mol KCl = about 74.5 g. 0.1 mol = 7.45 g KCl and that gives you 0.1 mol K^+. Therefore place 7.45 g KCl in some water, swirl until dissolved, add water to the 1 L mark, mix thoroughly.
Answered by
FS
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Answered by
Latera fekeda
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Answered by
Latera fekeda
Yes
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