In a trapezium ABCD,ABperpendicular DC.if angle A=4x degree,angle B=(6x+10degree),angle C=(3x-10degree) & angle D=5x degree.find each angle of trapezium.

Answer 1

The angle sum of a trapezium must be 360° , so

4x + 6x+10 + 3x-10 + 5x = 360
18x = 360
x = 20

angle A = 80°
angle B = 130°
angle C = 50°
angle D = 100°

I don't see any perpendicular sides.
Your question contains a contradiction.

Answer 2

I think he meant AB parallel to DC, if vertices are labeled in cyclic order