Asked by Wiped
What is the melting point of a mixture of 2.00 lb of NaCl and 12.00 pounds of ice if exactly half of the ice melts? Assume that all the NaCl disolves in the melted ice and that the van't Hoff factor for resulting solution is 1.44.
Answers
Answered by
DrBob222
6 lbs melted ice x 454 g/lb = ? grams H2O as the solvent.
2 lbs NaCl x 454 = ? grams NaCl.
delta T = i*Kf*m
i = 1.44
Kf = 1.86
You need m to solve for delta T.
mol NaCl = grams NaCl/molar mass NaCl
molality = moles NaCl/kg solvent.
delta T = i*Kf*m
Subtract delta T from 0 C to find melting point.
2 lbs NaCl x 454 = ? grams NaCl.
delta T = i*Kf*m
i = 1.44
Kf = 1.86
You need m to solve for delta T.
mol NaCl = grams NaCl/molar mass NaCl
molality = moles NaCl/kg solvent.
delta T = i*Kf*m
Subtract delta T from 0 C to find melting point.
Answered by
Anonymous
-3.15
Answered by
sai
-15.3
Answered by
cler
-15.280 degrees Celsius
Answered by
Anonymous
-15.3
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