In the reaction below, 22 g of H2S with excess

Question

O2 produced 10 g of sulfur.
?H2S + ?O2 ! ? S + ?H2O.
What is the percent yield of sulfur?
Answer in units of %

Answer 1

Balance the equation.
Convert 22 g H2S to mols. mols = grams/molar mass
Using the coefficients in the balanced equation, convert mols H2S to mols S.
Finally, convert mols S to grams S. g = mols x atomic mass. This is the theoretical yield (TY). Actual yield (AY) is 10 g from the problem.
%S = (AY/TY)*100 = ?

Answer 2

i got 8.71%

Answer 3

I don't think so. If you will post your work I will find the error for you.