Asked by Barb
What is the mass of hydrogen produced from the reaction of 2.31 grams of HCl with magnesium?
Answers
Answered by
Amanda
HCl + Mg2 ---> H2 + MgCl2
4HCl + Mg2 = 2H2 + 2MgCl2
4mol 2mol
2.31gr ?gr
HCl mole = 2.31/(1.008+35.45)=0.06 mol
4HCl/1H2
0.06mol HCl x (1molH2/4molHCl)= 0.015mol H2
mass of H2 = 0.015 x (2*1.0008) =0.03gram H2
i think that's how it works.. plz check your answer
4HCl + Mg2 = 2H2 + 2MgCl2
4mol 2mol
2.31gr ?gr
HCl mole = 2.31/(1.008+35.45)=0.06 mol
4HCl/1H2
0.06mol HCl x (1molH2/4molHCl)= 0.015mol H2
mass of H2 = 0.015 x (2*1.0008) =0.03gram H2
i think that's how it works.. plz check your answer
Answered by
DrBob222
The equation is
Mg + 2HCl ==> H2 + MgCl2
Convert 2.31 g HCl to mols. mols = g/molar mass.
Convert mols HCl to mols H2 using the coefficients in the balanced equation.
Convert mols H2 to grams.
grams = mols H2 x molar mass H2.
Post your work if you get stuck.
Mg + 2HCl ==> H2 + MgCl2
Convert 2.31 g HCl to mols. mols = g/molar mass.
Convert mols HCl to mols H2 using the coefficients in the balanced equation.
Convert mols H2 to grams.
grams = mols H2 x molar mass H2.
Post your work if you get stuck.
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