1)Solve 3+2(1-x)>6 or 2x+14<=8. Graph the solution set on a number line.

seem right to me.

You made an error in the first part.

for the first one you had
-2x>1
x> -1/2

when you divide by a negative, the inequality sign has to be reversed, so it is
x < -1/2

so that would be an open circle at -1/2 and the line going to the left.

since your relations are joined with OR and the second one is x < -3
the actual solution would be the first graph above.

To solve the inequality 3+2(1-x)>6, follow these steps:

1. Distribute the 2 to both terms inside the parentheses: 3+2-2x>6.
2. Combine like terms on the left side: 5-2x>6.
3. Subtract 5 from both sides: -2x>1.
4. Divide both sides of the inequality by -2. Since dividing by a negative number flips the inequality, remember to flip the sign: x<-1/2.

To solve the inequality 2x+14<=8, follow these steps:

1. Subtract 14 from both sides: 2x<= -6.
2. Divide both sides of the inequality by 2: x<= -3.

On the number line you provided, mark an open circle at -1/2 (excluding it because the inequality is strictly greater than) and draw an arrow to the right as the solution for the first equation. Mark a closed circle at -3 (including it because the inequality is less than or equal to) and draw an arrow to the left as the solution for the second equation.