1 Ci = 3.70E10 dps; therefore,
1 mCi = 1/1000 of that = 3.70E7 dps and that is 3.70E7 Bq
A 73-kg person is accidentally exposed for 215 s to a 16-mCi source of beta radiation coming from a sample of 14C.
What is the activity of the radiation source in disintegrations per second? In becquerels? (1 Ci = 3.70 1010 disintegrations/s.)
1)disintegrations/s
2)Bq
thanks for the help!!
1 mCi = 1/1000 of that = 3.70E7 dps and that is 3.70E7 Bq
Activity (disintegrations/s) = (Exposure Rate (Ci) * Conversion Factor (disintegrations/s)) / Exposure Time (s)
1 Ci (Curie) = 3.70 * 10^10 disintegrations/s
1) Activity in disintegrations per second:
First, convert the 16 mCi (milliCurie) to Ci by dividing it by 1000:
16 mCi = 16/1000 Ci = 0.016 Ci
Now, plug the values into the formula:
Activity (disintegrations/s) = (0.016 Ci * 3.70 * 10^10 disintegrations/s) / 215 s
Calculate the result:
Activity (disintegrations/s) = (0.016 * 3.70 * 10^10) / 215 ≈ 2.77 * 10^8 disintegrations/s
2) Activity in becquerels (Bq):
To convert the activity to becquerels, simply multiply the activity in disintegrations/s by the conversion factor (1 Ci = 3.70 * 10^10 disintegrations/s):
Activity (Bq) = Activity (disintegrations/s) * Conversion Factor (1 Ci = 3.70 * 10^10 disintegrations/s)
Plug in the value for the activity (disintegrations/s) calculated in step 1:
Activity (Bq) = 2.77 * 10^8 disintegrations/s * 3.70 * 10^10 disintegrations/s
Perform the multiplication to get the result:
Activity (Bq) = 1.0259 * 10^19 Bq (approximately)
So, the activity of the radiation source is approximately 2.77 * 10^8 disintegrations per second or 1.0259 * 10^19 becquerels.