Asked by beanstalk1
ball starts from rest under constant acceleration. If it travels a distance of 20.0 cm after time t, how far from the starting point is it after time 2t?
Answer
40.0 cm.
60.0 cm.
80.0 cm.
100.0 cm.
More information is needed to answer this question.
Answer
40.0 cm.
60.0 cm.
80.0 cm.
100.0 cm.
More information is needed to answer this question.
Answers
Answered by
Henry
D2/D1 = 0.5a*(2t)^2/0.5a*t^2.
D2/D1 = 0.5a*4t^2/0.5a*t^2
D2/D1 = 4t^2/t^2 = 4.
D2/20 = 4
D2 = 80 cm.
D2/D1 = 0.5a*4t^2/0.5a*t^2
D2/D1 = 4t^2/t^2 = 4.
D2/20 = 4
D2 = 80 cm.
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