Looks like you have to divide it up into two regions, joined at x=5
Integral[0,sqrt(5)] 2pi r*h dy
where r = y and h = 5-x = 5-y^2
and
Integral[sqrt(5),5] 2pi r*h dy
where r = y and h = 4y+5 - y^2
v = [25pi/2] + [40pi/3(10-sqrt(5)]
if that isn't what you get, check my math, but the formula for shells is just v = 2pi*r*h*dy with appropriate limits for y and values for r and h
Use the shell method to find the volume of the solid generated by revovling bounded by the curves and lines about the x-axis. y= sqrt(x) y=0 and y=(x-5)/4.
I tried thsi problem and got 775/6pi as the final exact answer and its wrong. please someone help!
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