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To find the side of the squares, you need to use the equation for the base of the solid, which is y = √lnx. To find the side of the squares, you need to evaluate the equation at the boundaries of the region (x = 1 and x = e). So, at x = 1, y = √ln1 = 0, and at x = e, y = √lne = 1. Therefore, the side of the squares is 1.
To find the volume of the solid, you need to use the formula for the volume of a solid of revolution, which is V = ∫a b πy2 dx. Substituting the equation for the base of the solid, y = √lnx, into the formula gives V = ∫1 e π(√lnx)2 dx. Evaluating the integral gives V = π(e - 1). Therefore, the volume of the solid is π(e - 1).
the basse of a solid S is the region enclosed by the graph of y=square root (ln x), the line x=e, and the x-axis. if the cross sections of S perpendicular to the x-axis are squares, then the volume of S is.
how do i find the side of the squares.
because i got square root(lnx) and squared it because Area of square is s^2.
then on my integrals, i would integrate it from 1 to e because that is the boundary. then what?
is what i am doing correct. i went to websites and looked in my book but i still am having trouble
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