Asked by Roy

Points A and B 1000 meter apart are plotted on a straight highway running east and west. from A, the bearing of tower C is N32*W and from be, the bearing of C is N64*E. approximate the shortest distance of the tower from the highway.

please explain........
Answered by Henry
The problem can be represented by a triangle with a base equal to 1000 m and
base angles A and B. The 3rd angle is C.

A = 90o-32o = 58o.
B = 90o-64o = 26o.
C = 180-58-26 = 96o.

c/sinC = a/sinA.
1000/sin96 = a/sin58
Multiply bothsides by sin58:
a = 1000*sin58/sin96 = 853 m.

b/sinB = c/sinC.
b/sin26 = 1000/sin96
b = 1000*sin26/sin96 = 441 m.

Side b represents the shortest dist.
from highway to Tower C.
Answered by dennis
PUTANGINAYO WALANG SAGOT SA TANONG KUNG BAKIT SIYA MAHALAGA
Answered by Bobo ni Dennis
Ikaw dennis, wala kang halaga sa mundo.
Answered by vhin
dennis yung titi mo , supot ... hehe
Answered by bahala na
Bakit wala yung sagot? sure na yan?
Answered by Heribert
373.81 m
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