Question
a boy throws a stone straight upward with an initial speed of 15 m/s on the surface of the earth. what maximum height above the starting point will the stone reach before falling back down?
Answers
Henry
h = (V^2-Vo^2)/2g
h = (0-225) / -19.6 = 11.48 m.
h = (0-225) / -19.6 = 11.48 m.