Asked by Donna
0.0158L of 0.25M HCL is needed to nutralize 22.0ml of a potassium hydroxide solution. Write the neutralization reaction then calculate the molar concentration of the KOH solution?
Answers
Answered by
DrBob222
KOH + HCl ==> KCl + H2O
mols HCl = M x L = ?
mols KOH = mols HCl (from the coefficients in the balanced equation)
M KOH = mols KOH/L KOH.
mols HCl = M x L = ?
mols KOH = mols HCl (from the coefficients in the balanced equation)
M KOH = mols KOH/L KOH.
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