Asked by charley

c) A 0.26-kg rock is thrown vertically upward from the top of a cliff that is 32 m high. When it hits the ground at the base of the cliff the rock has the speed of 29 m/s. Assuming that the air resistance can be ignored, find
i. the initial speed of the rock
(5 marks)
ii. the greatest height of the rock as measured from the base of the cliff.
Answered by bobpursley
Final KE=initial PE+initial KE
solve fodr initial KE, then vi

greatest height?

mgh=finalKE
Answered by Anonymous
25.18m/s