Question

A woman weighing 500 N stands in an elevator that is traveling upward. At a given instant the speed of the elevator as well as the women is 10m/s and both are decreasing at a rate of 2 m/s2 at that instant the elevator is exerts a force on the woman that is

Answer 1

a↓ mg↓ N↑
ma =mg-N
N=mg-ma =
=W-(W/g) •a=
=500 –(500/9.8) •2 =398 N