Asked by daniel
explain why f(x)=(1)/(x^2-9) is discontinoues at x=-3
Answers
Answered by
Steve
it is discontinuous there because division by zero is not defined.
A continuous function has no "holes" in it. f(x) is not defined for x = 3 or -3, because x^2-9 is zero there.
A continuous function has no "holes" in it. f(x) is not defined for x = 3 or -3, because x^2-9 is zero there.
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