Standard quadratic function with given vertex (h,k) is given by:
y=a(x-h)²+k
where a can be found by substituting the values of any given point on the curve.
Here, h=-2, k=5, so
y=a(x+2)²+5
Now substitute x=0, y=9 and solve for a.
Write the standard form of the quadratic function that has the indicated vertex and whose graph passes through the given point.
Vertex: (-2, 5)
Point: (0, 9)
1 answer
1 answer