Solve lim x->7+ as....sqrt(x-7)^3/(x-7). I found that it equals 0, but I don't know if I did everything right.

Similar Questions
  1. When I solve the inquality 2x^2 - 6 < 0,I get x < + or - sqrt(3) So how do I write the solution? Is it (+sqrt(3),-sqrt(3)) or
    1. answers icon 0 answers
    1. answers icon 2 answers
  2. Solve in the exact form.(sqrt of 4x+1)+(sqrt of x+1)=2 Someone showed me to do this next: Square both sides..so.. 4x+1+2((sqrt
    1. answers icon 4 answers
  3. Could someone show me how to solve these problems step by step....I am confused on how to fully break this down to simpliest
    1. answers icon 1 answer
more similar questions