Asked by Fai
A flask containing 5.00ml of 3M hcl solution required 14.45 of 1.00M naoh for titration. How many moles of hcl are present in the solution? The density of 3M hcl is 1.05g/ml.
My calculation
0.005L x 3M = 0.015 moles
0.01445 x 1m = 0.01445 moles
Who helps me to solve it
My calculation
0.005L x 3M = 0.015 moles
0.01445 x 1m = 0.01445 moles
Who helps me to solve it
Answers
Answered by
DrBob222
See your post above.
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