Ask a New Question
Search
Asked by
mo
what is the laplace transform of
5/2.e^t-3/2.e^-t
Answers
Answers
Answered by
Steve
L{e^t} = 1/(s-1)
L{e^-t} = 1/(s+a)
L is a linear transform, so
L{5/2.e^t-3/2.e^-t} = 5/2 L{e^t} - 3/2 L{e^-t}
= 5/2 * 1/(s-1) - 3/2 * 1/(s+1)
= (s+4)/(s^2-1)
Answered by
mo
compute the inverse laplace transform 2S^2+13S+5/(s+3)(s-1)^2
i got 3e^t+5e^t+3e^t, not sure it correct
Related Questions
Related
What is the laplace transform of (t^2)sin(t)?
What is the laplace transform of: f(t) = 0, 0<t<2 t, 2<t thanks!
what is the Laplace transform of e^4t(cos 2t) ?
the Laplace transform of e^4t(cos 2t)?? please i need help. thanks
Find the Laplace transform by using the theorem of L{f(t-a)H(t-a)}=(e^-as)F(s) L{(e^4t)H(t-10)}
Use the Laplace Transform to solve this initial value problem. y'''' - 8y = 0, y'(0)=63, y''(0)=2...
laplace transform of f(t) = t sin (at) use integration by parts
inverse Laplace transform of 2s/(4s²+6s+1)
Use laplace transform to solve : f'(x) - f(x) =e^-x