Question

A car starting at x = 49 m accelerates from rest at a constant rate of 8.0 m/s2.
(a) How fast is it going after 10 s?
(b) How far has it gone (from x = 0) after 10 s?
(c) What is its average velocity for the interval 0 t 10 s?

NEED HELP!!!

Answers

bobpursley
vf=at

b. distance=49+1/2 a t^2

c. avgvelocity=vf/2

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