vf=at
b. distance=49+1/2 a t^2
c. avgvelocity=vf/2
A car starting at x = 49 m accelerates from rest at a constant rate of 8.0 m/s2.
(a) How fast is it going after 10 s?
(b) How far has it gone (from x = 0) after 10 s?
(c) What is its average velocity for the interval 0 t 10 s?
NEED HELP!!!
1 answer