estimates, using values of n from 5 to 50:
5: 56.0341
10: 56.0401
15: 56.0434
20: 56.0456
25: 56.0471
30: 56.0483
35: 56.0491
40: 56.0498
45: 56.0503
50: 56.0507
wolframalpha.com calculates 56.0528
just type in
arc length 56cos(x), x = 0 .. pi/2
If you can program a calculator or computer, estimate the length of the curve f(x) on the given interval using largest n's.
f(x)=56cos(x), for x is greater than/equal to 0 and x is smaller than/equal to pi/2.
2 answers
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