Asked by KC
Answer check please: Consider the circle (x-3)^2 + (y+1)^2 = 169. The point (15,4) is on the circle. Find an equation for the line that is tangent to the circle at this point. I got y= 5/12x-9/4.
Answers
Answered by
Henry
C(3,-1), P(15,4).
m1 = (4+1) / (15-3) = 5/12.
m2 = -12/5 = Negative reciprocal 0f m1.
P(15,4).
Y = mx + b = 4.
(-12/5)15 + b = 4
-36 + b = 4
b = 40.
Eq: Y = (-12/5)x + 40.
m1 = (4+1) / (15-3) = 5/12.
m2 = -12/5 = Negative reciprocal 0f m1.
P(15,4).
Y = mx + b = 4.
(-12/5)15 + b = 4
-36 + b = 4
b = 40.
Eq: Y = (-12/5)x + 40.
Answered by
abubetter1
what angle does an arc 6.6cm in length substend at the centre of a circle of radius 14cm if ^=22/7
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.