Asked by Cin
A person drops a small rock from a bridge. If it takes 1.70 seconds for the rock to reach the water below the bridge, how high was the bridge above the water? please explain.
Answers
Answered by
drwls
The distance it falls in t seconds after being dropped is
H = (1/2) g t^2
g is the acceleration of gravity, which you must have learned about by now. It is 9.8 m/s^2 on Earth.
Set t = 1.7 seconds and use the formault to solve for the height, H, in meters.
H = (1/2) g t^2
g is the acceleration of gravity, which you must have learned about by now. It is 9.8 m/s^2 on Earth.
Set t = 1.7 seconds and use the formault to solve for the height, H, in meters.
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