Asked by greeny
over the years, the thermite reaction has been used for welding railorad rails, in incendiary bombs, and to ignite solid fuel rocket motors. The reaction:
Fe2O3(s) + 2 Al (s) -> 2 Fe(l) + Al2O3 (s)
What masses of iron ( III) oxide and aluminum must be used to produce 15.0 grams of iron? What is the maximum mass of aluminum oxide that could be produced?
Fe2O3(s) + 2 Al (s) -> 2 Fe(l) + Al2O3 (s)
What masses of iron ( III) oxide and aluminum must be used to produce 15.0 grams of iron? What is the maximum mass of aluminum oxide that could be produced?
Answers
Answered by
Steve
15g of Fe is 15/55.845 = 0.2686 moles
Each mole of Fe requires 1 mole of Fe2O3 and 2 moles of Al.
mol wt Fe2O3 = 2*55.845+3*15.999 = 159.687
mol wt Al = 26.982
so, we need
.2686*159.687 = 42.9g Fe2O3
.2686*2*26.982 = 14.5g Al
mol wt Al2O3 = 2*26.982+3*15.999 = 101.961
so, we get .2686*101.961 = 68.9g Al2O3
Each mole of Fe requires 1 mole of Fe2O3 and 2 moles of Al.
mol wt Fe2O3 = 2*55.845+3*15.999 = 159.687
mol wt Al = 26.982
so, we need
.2686*159.687 = 42.9g Fe2O3
.2686*2*26.982 = 14.5g Al
mol wt Al2O3 = 2*26.982+3*15.999 = 101.961
so, we get .2686*101.961 = 68.9g Al2O3
Answered by
C'm mulerk
We first check if the equation is balanced and according to our equation its already balanced.2nd we find the ratios from the equation.
FeO3+2AL=2Fe+AL2O3
2 = :2
x = :mass over
rmm=the answer you u will find when u do mol=mass/rmm.
Then n=mass/molar mass
Mass=mol x rmm
mass=0.134 x 159.6
21.359.final
FeO3+2AL=2Fe+AL2O3
2 = :2
x = :mass over
rmm=the answer you u will find when u do mol=mass/rmm.
Then n=mass/molar mass
Mass=mol x rmm
mass=0.134 x 159.6
21.359.final
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