Asked by Nett
x 2/3-16x 1/3 +64=0
Answers
Answered by
Steve
if you let u = x^1/3, you can express the polynomial as
u^2 - 16u + 64 = 0
(u-8)^2 = 0
u = 8
So, since x = u^3,
x = 512
u^2 - 16u + 64 = 0
(u-8)^2 = 0
u = 8
So, since x = u^3,
x = 512
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