Asked by Brittany
If you walk for 1.66min at a speed of 1.22m/s and then run for 1.66min at 3.05m/s along a straight track, what is the average velocity?
Answers
Answered by
Steve
analytical way:
total distance = 1.66*60*1.22 + 1.66*60*3.05 = 425.292m
total time = 1.66+1.66min = 199.2 sec
avg speed: 425.292m/199.2s = 2.135 m/s
easy way: equal times, so speed is average of 1.22 and 3.05 = 2.135 m/s
total distance = 1.66*60*1.22 + 1.66*60*3.05 = 425.292m
total time = 1.66+1.66min = 199.2 sec
avg speed: 425.292m/199.2s = 2.135 m/s
easy way: equal times, so speed is average of 1.22 and 3.05 = 2.135 m/s
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